4x=(4/3)x^2

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Solution for 4x=(4/3)x^2 equation:


x in (-oo:+oo)

4*x = (4/3)*x^2 // - (4/3)*x^2

4*x-((4/3)*x^2) = 0

(-4/3)*x^2+4*x = 0

4*x-4/3*x^2 = 0

DELTA = 4^2-(-4/3*0*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-4)/(-4/3*2) or x = (-16^(1/2)-4)/(-4/3*2)

x = 0 or x = 3

x in { 0, 3 }

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